MATH SOLVE

4 months ago

Q:
# A man on the third floor of a building shouts down to a person on the street. If the man is 25 feet up and the distance between the person on the street and the man in the building is 50 feet, what is the angle of elevation (in degrees) between the person on the street and the person in the building?

Accepted Solution

A:

You have that the man is 25 feet up and the distance between the person on the street and the man in the building is 50 feet. Therefore, you mus aplpy the proccedure below to solve this exercise:

Tan^-1(α)=Opposite/Adjacent

α is the angle of elevation.

Opposite=25 feet

Adjacent=50 feet

When you substitute these values into Tan^-1(α)=Opposite/Adjacent, you obtain:

Tan^-1(α)=Opposite/Adjacent

Tan^-1(α)=25/50

α=26.56°

Therefore, the answer is: 26.56°

Tan^-1(α)=Opposite/Adjacent

α is the angle of elevation.

Opposite=25 feet

Adjacent=50 feet

When you substitute these values into Tan^-1(α)=Opposite/Adjacent, you obtain:

Tan^-1(α)=Opposite/Adjacent

Tan^-1(α)=25/50

α=26.56°

Therefore, the answer is: 26.56°