MATH SOLVE

2 months ago

Q:
# RepostedErika plays basketball and started a tournament with 15 three-point shots on the season. The graph relates her total season three-pointers with the number of games played in the tournament.Which equation in standard form represents the relationship shown in the graph?y−23=4(x−2)y = 4x + 154x + y = 15−4x+y=15y=−4x+15

Accepted Solution

A:

Answer:4. [tex]-4x+y=15[/tex] Step-by-step explanation:We have been given a graph of a linear function and we are asked to find the correct equation representing the relationship shown in the graph.Since we know that the standard form of an equation is in form: [tex]Ax+By=C[/tex], where A, B and C are integers.First of all we will find the slope of our line and write equation of line in slope-intercept form. Then we will change it into standard form. [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex][tex]m=\frac{23-15}{2-0}[/tex] [tex]m=\frac{8}{2}=4[/tex]Slope of our line is 4. We can see that y-intercept (b) is 15. Now let us write equation of our line in slope-intercept form.[tex]y=mx+b[/tex] [tex]y=4x+15[/tex]Now we will change our given equation into standard form by subtracting 4x from both sides of our equation. [tex]-4x+y=4x+15-4x[/tex][tex]-4x+y=15[/tex] Therefore, the equation [tex]-4x+y=15[/tex] represents the relationship shown in the graph in standard form and 4th option is the correct choice.